A coil of resistance `100 Omega` is connected across a battery of `emf 6.0 V`. Assume that the heat developed in the coul is used to raise its temperature. If the heat capacity of the coil is `4.0 J K^(-1)`, how long will it take to raise the temperature of the coil by `15^@ C`?

Answer

B

Explanation

`R = 100 Omega, E =6V`
`DeltaT = 15^@C`
` Heat capacity of the coil = `
`(4J)/(K)`
`36)/(100)xxt =60`
`t =(6000)/(30) = (1000)/(6)`
`= 166.67 sec`
=166.67)/(60)`
`= 2.8 min`