A beam of protons with a velocity of `4 X 10 ^5 ms^(-1)` enters a uniform magnetic field of 0.3 T. The velocity makes an angle of `60^@` with the magnetic field. Find the radius of the helicla path taken by the proton beam and the pitch of the helix.

Explanation

To solve the problem step by step, we will calculate the radius of the helical path taken by the proton beam and the pitch of the helix.

### Given Data:
- Velocity of protons, \( v = 4 \times 10^5 \, \text{m/s} \)
- Magnetic field strength, \( B = 0.3 \, \text{T} \)
- Angle with the magnetic field, \( \theta = 60^\circ \)
- Charge of proton, \( q = 1.6 \times 10^{-19} \, \text{C} \)
- Mass of proton, \( m = 1.67 \times 10^{-27} \, \text{kg} \)
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