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a charged particle moves in a gravity fr...

a charged particle moves in a gravity free space without change in velocity. Which of the following is/are possible?

A

`E=0 `,`B=0`

B

`E=0 `,`B!=0`

C

`E!=0 `,`B=0`

D

`E!=0 `,`B!=0`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question regarding the motion of a charged particle in a gravity-free space without a change in velocity, we need to analyze each option provided. ### Step-by-Step Solution: 1. **Understanding the Problem**: - A charged particle is moving in a gravity-free space. - Its velocity is constant, meaning there is no net force acting on it (according to Newton's first law). 2. **Identifying Forces**: - The forces acting on a charged particle can be due to an electric field (E) and a magnetic field (B). - The force due to an electric field is given by \( F_E = Q \cdot E \). - The force due to a magnetic field is given by \( F_B = Q \cdot (V \times B) \), where \( V \) is the velocity of the particle. 3. **Analyzing Each Option**: - **Option A: \( E = 0 \) and \( B = 0 \)**: - If both electric and magnetic fields are zero, then \( F_E = 0 \) and \( F_B = 0 \). - Therefore, the net force \( F = F_E + F_B = 0 \). - The particle will continue to move with constant velocity. This option is **possible**. - **Option B: \( E = 0 \) and \( B \neq 0 \)**: - Here, \( F_E = 0 \) and \( F_B \neq 0 \). - The magnetic force \( F_B \) can be zero if the velocity vector \( V \) is parallel to the magnetic field \( B \) (i.e., \( V \times B = 0 \)). - Thus, this option is **possible** under the condition that \( V \) is parallel to \( B \). - **Option C: \( E \neq 0 \) and \( B = 0 \)**: - In this case, \( F_E \neq 0 \) and \( F_B = 0 \). - Since there is a non-zero electric field, the force \( F_E \) will cause the particle to accelerate, changing its velocity. This option is **not possible**. - **Option D: \( E \neq 0 \) and \( B \neq 0 \)**: - Here, both forces \( F_E \) and \( F_B \) are non-zero. - The particle can still maintain a constant velocity if the forces are equal in magnitude but opposite in direction (i.e., \( F_E + F_B = 0 \)). This is possible under specific conditions. Thus, this option is **possible**. 4. **Conclusion**: - The possible options for the charged particle moving without a change in velocity are: - **Option A**: \( E = 0 \), \( B = 0 \) - **Option B**: \( E = 0 \), \( B \neq 0 \) (if \( V \) is parallel to \( B \)) - **Option D**: \( E \neq 0 \), \( B \neq 0 \) (if forces balance each other) ### Final Answer: The correct options are **A, B, and D**. ---
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