A magnetic field of `(4.0 X10^(-3)vec k)` T exerts a force of `(4.0veci +3.0vecj x 10^(-10)` N on a particle having a charge of `1.0X10^(-9)` C and going in the x-y plane. Find the velocity of the particle.

Explanation

To find the velocity of the particle in the given magnetic field, we can use the formula for the magnetic force acting on a charged particle moving in a magnetic field. The force \( \vec{F} \) is given by:

\[ \vec{F} = q (\vec{v} \times \vec{B}) \]

where:
- \( \vec{F} \) is the magnetic force,
...