A particle having a charge of `2.0X10^(-8) C` and a mass of `2.0X10^(-10)g` is projected with a speed of `2.0X10^3 ms^(-1)` in a region having a uniform magnetic field of 0.10 T. The velocity is perpendicular to the field. Find the radius of the circle formed by the particle and also the time period.

Explanation

` q = 2.0 xx 10 ^(-6) C,`
`B = 0.10T `
` m = 2.0 xx 10^(-10) kg`
`= 2 xx 10 ^(-10)kg,`
` V =m 2.0 xx 10^(3) m/s `
Using qVB = (mV^(2)/(r) `
` So , radius r = (mV)/(qB)= 20 cm `
` T= (2 pi r) /((v)`
`So , T = 6.28 xx 10 ^(-4)s` .