A proton is projected with a velocity of `3X10^6 m s ^(-1)` perpendicular to a uniform magnetic field of 0.6 T. find the acceleration of the proton.

Explanation

` ma = qVB `
`a = (qVB)/(m)`
`= (1.6 xx 10^(-10) xx 3 xx10^(0) xx 0.6` )/(167 xx 10^(-17)`
` = 1.72 xx 10^(14) m/s ^(2)` .