A particle moves in a circle of diameter 1.0 cm under the action of magnetic field of 0.40 T, An electric field of `200 V m^(-1)` makes the path straight. Find the charges/mass ratio of the particle.

Explanation

`r = 0.5 xx 10^(-2) m, B = 0.4t , E = 200v/s `
The path will straighten if
` qE = qVB `
` rArr V=( €)/(B) = 500 m/s`
since `r = (mV)/(qB)`
`(q)/(B) = (V)/rB) = 2.5 xx 10^(6) C/kg`.