A particle having mass m and charge q is released from the origin in a region in which electric field and magnetic field are given by
` vecB =- B_0vecJ and vecE = E_0 vecK.`
Find the speed of the particle as a function of its z-coordinate.

Explanation

Velocity will be along `x- z plane - barB`
`= - barB_(0) barJ, barE = E_(0) barK`
`F = q(E+ V xx B)`
`= qE_(0)K - qV_(x) B_(0)K + qV_(x) B_(0) I`
`Since V_(x)= 0, F_(2) = qE_(0)`
so `a = (qE_(0))/(m)`
`:. V^(2) = u^(2) +2as = 2 (qE_(0_))/(m) z`
`so , v = sqrt((2qE_(0) z) /(m))`
[dist along z - direction be z ].