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A rectangular coil of 100 turns has leng...

A rectangular coil of 100 turns has length 5 cm and width 4 cm. it is placed with its plane parallel to a uniform magnetic field and a current of 2 A is sent through the coil. Find the magnitude of the magnetic field B, if the torque acting on the coil is `0.2 Nm^(-1).`

Text Solution

AI Generated Solution

To solve the problem step by step, we will use the formula for torque acting on a rectangular coil in a magnetic field. The torque (τ) on a coil is given by the formula: \[ \tau = n \cdot B \cdot I \cdot A \cdot \sin(\theta) \] Where: - \( \tau \) = Torque (in Nm) ...
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Knowledge Check

  • A rectangular coil has 100 turns has length 5 cm and breadth 2 cm. It is suspended in radial magnetic field of induction 0.1 Wb//m^(2) . If a current of 100 muA is passed through the coil, then the torque acting on the coil is

    A
    `10^(-6)` N m
    B
    `10^(-7)` N m
    C
    `10^(-5)` N m
    D
    `10^(-8)` N m
  • A circular coil of 1 turn and area 0.01m^(2) carries a current of 10A . It is placed in a uniform magnetic field of induction 0.1 tesla such that the plane of the circle is perpendicular to the direction of the field, the torque acting on the coil is

    A
    `0.1Nm`
    B
    `0.001Nm`
    C
    `0.01Nm`
    D
    Zero
  • A circular coil of 25 turns and radius 12 cm is placed in a uniform magnetic field of 0.5 T normal to the plane of the coil. If the current in the coil is 6 A then total torque acting on the coil is

    A
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    B
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