A copper wire of diameter 1.6 mm carries a current of 20A. Find the maximum magnitude of the magnetic field (vec B)due to this current.

Explanation

To find the maximum magnitude of the magnetic field (B) due to a current-carrying copper wire, we can use the formula for the magnetic field around a long straight conductor:

\[ B = \frac{\mu_0 I}{2 \pi d} \]

Where:
- \( B \) is the magnetic field,
- \( \mu_0 \) is the permeability of free space (\( 4\pi \times 10^{-7} \, \text{T m/A} \)),
- \( I \) is the current in amperes (A),
...