Home
Class 12
PHYSICS
Each of the batteries shown in figure ha...

Each of the batteries shown in figure has an emf equal to 5 V. Show that the magnetic field B at the point P is zero for any set of values of the resistances .

Text Solution

Verified by Experts

Net current in the circuit = 0
[from wheatstpone bridge principle]
Hence net magnetic field = 0.
Promotional Banner

Topper's Solved these Questions

  • MAGNETIC FIELD DUE TO CURRENT

    HC VERMA|Exercise Objective 2|7 Videos

  • MAGNETIC FIELD

    HC VERMA|Exercise Exercises|61 Videos

  • MAGNETIC PROPERTIES OF MATTER

    HC VERMA|Exercise Exercises|9 Videos

Similar Questions

Explore conceptually related problems

Find the magnetic field B at the point P in figure

The segment of wire shown in figure carries a current of i=5 A. The magnetic field (in Tesla) at the point P is

Each of the resistors shown in figure has a resistances of 10(Omega) and each of the batteries has an emf of 10V.Find the currents through the resistors a and b in the two circuits.

Figure shows two identical magnetic dipoles a and b of magnetic moments M each, placed at a separation d , with their axes perpendicular to each other. Find the magnetic field at the point P midway between the dipoles.

A 6V battery of negligible internasl resistance is connected across a uniform wire AB of length 10 cm . The positive terminal of another battery of emf 4 V and internal resistance 1Omega is joined to the point A as shown in figure. Take the potentail at B to be zero. a. What are the potential at the ponts A and C ? b. At which point D of the wire AB , the potential is equal to the potential at C ? c. If the points C and D are connected by a wiere, what will be the current through it ? d. If the 4V battery is replaced by 7.5 V battery, what would be the answer of parts (a) and (b)?

In the network shown in the figure, each of the resistance is equal to 2 Omega . The resistance between the points and B is

HC VERMA-MAGNETIC FIELD DUE TO CURRENT-Exercises
  1. Find the magnetic field B at the centre of a rectangular loop of lengt...

    Text Solution

    |

  2. A regular polygon of n sides is formed by bending a wire of total leng...

    Text Solution

    |

  3. Each of the batteries shown in figure has an emf equal to 5 V. Show th...

    Text Solution

    |

  4. A straight , long wire carries a current a current of 20A. Another wir...

    Text Solution

    |

  5. Three coplanar parallel wires, each carrying a current of 10 A along t...

    Text Solution

    |

  6. Two parallel wires separated by a distance of 10cm carry currents of 1...

    Text Solution

    |

  7. Figure shows a part of an electric circuit. The wires AB, CD, and EF a...

    Text Solution

    |

  8. A long, straight wire is fixed horizontally and carries a current of 5...

    Text Solution

    |

  9. A square loop PQRS carrying a current of 6.0 A is placed near a long w...

    Text Solution

    |

  10. A circular loop of one turn carries a current of 5.00 A. If the magnet...

    Text Solution

    |

  11. A current - carrying circular coil of 100 turns and radius 5.0 cm pro...

    Text Solution

    |

  12. An electron makes (3 xx 10^5) revolutions per second in a circle of ra...

    Text Solution

    |

  13. A conducting circular loop of radius a is connected to two long, strai...

    Text Solution

    |

  14. Two circular coils of radii 5.0 cm and 10 cm carry equal currents of 2...

    Text Solution

    |

  15. If the outer coil of the precious problem is rotated through 90^@ abo...

    Text Solution

    |

  16. A circular loop of radius 20 cm carries a current of 10 A. An electron...

    Text Solution

    |

  17. A circular loop of radius R carries a current I. Another circular loop...

    Text Solution

    |

  18. A circular loop of radius r carrying a current i is held at the centre...

    Text Solution

    |

  19. Find the magnetic field B due to a semicircular wire of radius 10.0 cm...

    Text Solution

    |

  20. A piece of wire carrying a current of 6.00 A is bent in the form of a ...

    Text Solution

    |