The magnetic field B inside a long solenoid, carrying a current of 5.00 A, is `(3.14 xx 10^-2)` T. Find the number of turns per unit length of the solenoid.

Explanation

To find the number of turns per unit length of a solenoid given the magnetic field inside it, we can use the formula for the magnetic field inside a long solenoid:

\[ B = \mu_0 n I \]

Where:
- \( B \) is the magnetic field inside the solenoid (in Tesla),
- \( \mu_0 \) is the permeability of free space (\( 4\pi \times 10^{-7} \, \text{T m/A} \)),
- \( n \) is the number of turns per unit length (in turns/m),
...