The horizontal component of the earth's magnetic field is `3.6 xx 10^(-5) T` where the dip is `60^@`. Find the magnitude of the earth's magnetic field.

Explanation

To find the magnitude of the Earth's magnetic field given the horizontal component and the angle of dip, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the given values**:
- Horizontal component of the Earth's magnetic field, \( B_H = 3.6 \times 10^{-5} \, \text{T} \)
- Angle of dip, \( \delta = 60^\circ \)

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