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At 45^@ to magnetic meridian, the appare...

At `45^@` to magnetic meridian, the apparent dip is `30^@`. What is the true value of dip?

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At `45^@` to the magnetic meridian, the effective horizontal component of the earth's magnetic field is `B'_H = B_H cos 45^@ = 1/(sqrt(2)) B_H`. The apparent dip `delta` is given by
`(tandelta' = (B_v)/(b'_H) = (sqrt(2) B_v))/(B_H) = sqrt(2) tandelta`
or, `delta = tan^(-1) sqrt(1/6)`.
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HC VERMA-PERMANENT MAGNETS-Exercises
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  14. The magnetic field due to the earth has a horizontal component of 26 m...

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  15. A magnetic needle is free to rotate in a vertical plance which makes a...

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  16. The needle of a dip circle shows an apparent dip of 45^@ in a particul...

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  17. A tangent galvanometer shown a deflection of 45^@ when 10 mA of curren...

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