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A tangent galvanometer has 66 turns and ...

A tangent galvanometer has 66 turns and the diameter of its coil is 22cm. It gives a deflection of `45^@ for 0.10 ` A current. What is the value of the horizontal component of the earth's magnetic field?

Text Solution

Verified by Experts

For a tangent galvanometer `I = K tantheta`
`= (2r B_H)/(mu_0 n) tantheta`
or, `B_H = (mu_o ni)/(2r tantheta)`
`= ((4pi xx 10^(-7) Tm/A) xx 66 xx (0.1 A))/((22 xx 10^(-2) m) (tan 45^@))`
`= 3.8 xx 10^(-5) T`
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Knowledge Check

  • When a current of 318 m A is passed through a tangent galvanometer , a deflection of 45^@ is obtained. If radius of coil is 10 cm and number of turns 50 , then what is a value of horizontal component of earth's magnetic field ?

    A
    `10^-6 T`
    B
    `10^-7 T`
    C
    `10^-2 T`
    D
    `10^-4 T`

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