Two long bar magnets are placed with their axes coinciding in such a way that the north pole of the first magnet is 2.0cm from the south pole of the second. If both the magnets have a pole strength of `10 Am`, find the force exerted by one magnet on the other.

Explanation

Here `M_(1) = M_(2) = 10Am`
`and r = 2cm = 0.02m`
we know that
From exterted by two magnitic poles on each other
`= (mu_(0))/(4pi)(M_(1)M_(2))/(r^(2))`
`= (4 pi xx 10^(-7)xx10^(2))/(4 pi xx 4 xx 10^(-4))`
`= 2.5 xx 10^(-2)N`