A magnetic dipole of magnetic moment `1.44 A m^2` is placed horizontally with the north pole pointing towards north. Find the positon of the neutral point if the horizontal component of the earth's magnetic field is `18 muT`.

Explanation

We know for a magnetic dipole with its pole pointing to the north , the pole in the broadsides on position
Again `vacB` an this cases`(mu_(0)M)/(4 pi d^(3))`
`= vacB a`due to erth
`rArr (10^(-7) xx 1.44)/(d^(2))= 18 xx 10^(-6)`
`rArr d_(s) = 8 xx 10^(-3)`
`d = 2xx 10^(-1)= 20 cm`
in the plane bisecting the dipole