A magnetic dipole of magnetic moment `0.72(sqrt(2) Am^2)` is placed horizontally with the north pole pointing towards east. Find the position of the neutral point if the horizontal component of the earth's magnetic field is `18 muT`.

Explanation

Here Magniticc moment
`= 0.75 sqrt(2) A - m^(2) = M`
`B_(H) = 18 mu T`
`:' B = (mu_(0))/(4 pi)(M)/(d^(3))`
`rArr (4 pi xx 10^-7))/(4 pi) xx (0.72 sqrt(2))/(d^(3)) = 18 xx 10^(-6)`
rArr d^(3) = (0.72 xx 1.414 xx 10^(-7))/(18 xx 10^(-3))`
`= 0.005656`
`rArr d = sqrt(0.005656)`
`= 0.2 m = 20 cm`