The magnetic field `B` and the magnetic intensity `H` in a material are found to be `1.6 T and 1000 A m^(-1)` respectively. Calculate the relative permeability `mu`, and the susceptibiliyt `chi` of the material.

Explanation

Here`B =1.6T,H =1000 A//m`
`and mu= B/H=1.6/1000`
`=1.6xx10^(-3)`
` mu_r= (mu)/(mu_0)=(1.6xx10^(-3))/(4 pi xx10^(-7))`
`=0.127xx10^(4)`
`1.3xx10^(3)`
`mu= mo_0 xx(1+x)`
`x=(mi//mu_0)^(-1)=(mu_r)-1`
`=1.3xx10^(3)-1`
`=1300-1`
`=1233=1.299xx10^(3)`
`~~1.3xx10^(3)`.