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A 12 V battery connected to a 6 Omega, 1...

`A 12 V` battery connected to a `6 Omega, 10 H `coil through a switch drives a constant current in the circuit. The switch is suddenly opened. Assuming that it took 1 ms to open the switch, calculate the average emf induced across the coil.

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To solve the problem step by step, we will follow these calculations: ### Step 1: Calculate the initial current (I1) in the circuit The initial current flowing through the circuit can be calculated using Ohm's Law: \[ I = \frac{E}{R} \] Where: - \( E = 12 \, V \) (voltage of the battery) - \( R = 6 \, \Omega \) (resistance) ...
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A 10 V battery connected to 5omega resistance coil having inductance 10 H through a switch drives a constant current in the circuit. The switch is suddenly opened and the time taken to open it is 2ms. The average emf induced across the coil is

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A 35.0 V battery with negligible internal resistance, a 50.0Omega resistor, and a 1.25 mH inductor with negligible resistance are all connected in series with an open switch. The switch is suddenly closed (a) How long after closing the switch will the current through the inductor reach one-half of its maximum value? (b) How long after closing the switch will the energy stored in the inductor reach one-half of its maximum value?

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