A wire of length 10cm translates in a direction making an angle of `60^@` with its length. The plane of motion is perpendicular ot a uniform magnetic field of 1.0 T that exists in the space. Find the emf induced between the ends of the rod if the speed of translation of `20 cm s^(-1).

Explanation

Here`1=10cm=0.1m`
`theta=60^(@),B=1T,`
`v=20 cm//s=0.2m//s`
`e=Bvl sin 60^(@)`
`[ As we have to take that component of length vector which is perpendicular to the velocity vector]=1.732xx10^(-2)`
`=17.32xx10^(-3)V.`