Shows a conducting circular loop of radius a placed in a uniform, perpendicular magnetic field B. A thick metal rod OA is pivoted at the centre O. The other end of the rod touches the loop at A. The centre O and a fixed point C on the loop are connected by a wire OC of resistance R. A force is applied at the middle point of the rod OA perpendicularly, so that the rod rotates clockwise at a uniform angular velocity `omega`. Find the force.

Explanation

e=Bvl=(Bxxaxx omegaxxa)/2`
i= (Ba^2 omega)/(2R)`
`F=ilB=(Ba^2 omega)/(2R)xxaxxB`
`(Ba^2 omega)/(2R) towards right of OA.`.