Home
Class 12
PHYSICS
An AC source producing emf epsilon = e...

An AC source producing `emf`
`epsilon = epsilon_0 [cos(100 pi s^(-1)) t + cos (500 pi s^(-1))t]`
is connected in series with a capacitor and a resistor. The steady-state current in the circuit is found to be
`I = i_1 cos [(100 pi s^(-1) t + varphi_1] + i_2 cos [(500 pi s^(-1))t +phi_2]`.

A

`i_1 gt i_2`

B

`i_1 = i_2`

C

`i_1 lt i_2`

D

The information is insufficient to find the relation between `i_1 and i_2`.

Text Solution

Verified by Experts

The correct Answer is:
C
Promotional Banner

Topper's Solved these Questions

  • ALTERNATING CURRENT

    HC VERMA|Exercise Objective 2|7 Videos

  • ALTERNATING CURRENT

    HC VERMA|Exercise Exercises|19 Videos

  • ALTERNATING CURRENT

    HC VERMA|Exercise Short Answer|13 Videos

  • BOHR'S MODEL AND PHYSICS OF THE ATOM

    HC VERMA|Exercise Exercises|46 Videos

Similar Questions

Explore conceptually related problems

An AC voltage e=e_(0)sin50t-e_(0)cos100pit is connected in series with a resistor and capacitor. The steady state current through circuit is found to be I=I_(0)sing(50pit+phi)+I_(0)'cos(100pit+phi_(2)) Then, the ratio of (I_(0))/(I_(0)' is

Find the effective value of current i=2+4 cos 100 pi t .

Find the effective value of current. i=2 sin 100 (pi)t + 2 cos (100 pi t + 30^(@)) .

Voltage and current in an ac circuit are given by V=5 sin (100 pi t-pi/6) and I=4 sin (100 pi t+pi/6)

int_(0)^(10 pi)cot^(-1)(cos t)dx

The time constant of an LR circuit is 40 ms. The circuit is connected at t= 0 and the steady state current is found ot be 2.0 A. Find the current at (a) t= 10 ms (b) t =20ms, (c ) t =100ms and (d) t = 1 s.

I=int_(0)^(2 pi)cos^(-1)(cos x)dx

" (i) "cos^(-1){cos(-(pi)/(4))}