Consider the situation of the previous problem. Find the average electric field energy stored in the capacitor and the average magnetic field energy stored in the coil.

Explanation

Given `R=300 Omega`, `C= 20 mu F`
`=20 xx 10^-6F`, `L=1H`, `Z=500`(from 14) ,`E_0 = 50 V`, `i_0= E_0/Z = 50 /500 =0.1A`
Electrical energy stored in capacitor
`=1/2 CV^2`
`=1/2 xx 20 xx 10^-5 xx 50 xx 50`
`=25 xx 10^-3J = 25mJ`.
Magnetic field energy stored in the coil
`=1/2 Li_0^2`
`=1/2 xx 1 xx (0.1)^2`
`=1/2 xx 1 xx 10^-2 = 5 xx 10^-3J`
`=5mJ`