The electric field in an electromagnetic wave is given by `E( 50N (C^-1)) sin omega (t-x/c).` Find the energy contained in a cylinder of cross section 10 cm^2 and length 50 cm along the x- axis.

Explanation

To find the energy contained in a cylinder of cross-section 10 cm² and length 50 cm along the x-axis, we can follow these steps:

### Step 1: Identify the Given Values
- The electric field \( E_0 = 50 \, \text{N/C} \)
- Cross-sectional area \( A = 10 \, \text{cm}^2 = 10 \times 10^{-4} \, \text{m}^2 = 1 \times 10^{-3} \, \text{m}^2 \)
- Length of the cylinder \( L = 50 \, \text{cm} = 0.5 \, \text{m} \)

### Step 2: Calculate the Energy Density
...