Consider the situation of the previous problem. Define displacement resistance `(R_d = V/i_d)` of the space between the plates where V is the potential difference between the plates and `i_d` is the displacement current. Show that `R_d` varies with time as ` (R_d)= (R(e^(t/tau)-1).)

If the potential difference between A and D is V, what will be potential difference between F and C. each of the resistance is R.

The force between the plates of a parallel plate capacitor of capacitance C and distance of separation of the plates d with a potential difference V between the plates, is.

A parallel plate capacitor is connected to an ideal battery of emf E through a resistance R and a switch. Area of the plates of capacitor is A, and d is the separation between them. Resistance to the displacement current can be defined as R_d = V//i_d , where V and i_d are instantaneous potential difference between the plates and displacement current, respectively. Find displacement resistance as a function of time.

In a parallel plate capacitor, the distance between the plates is d and potential difference across the plate is V . Energy stored per unit volume between the plates of capacitor is

If the circuit a potential difference of 3V is required between the point C and D . Find the value of resistance r_(2)

A uniformly distributed space charge fills up the space between two large parallel plates separated by a distance d . The potential difference between the plates is equal to zero ? What will then be the field strength near the other plate ?

An electron having charge e and mass m starts from the lower plate of two metallic plates separated by a distance d . If the potential difference between the plates is V , the time taken by the electron to reach the upper plate is given by .