A monochromatic light source of intensity 5 m W emits `(8xx10^15)` photons per second . This light ejects photoelectrons from a metal surface. The stopping potential for this setup is 2.0 V. Calculate the work function of the metal.

Explanation

To solve the problem, we need to calculate the work function of the metal using the given data. Here’s a step-by-step solution:

### Step 1: Understand the Given Data
- **Intensity (I)** of the light source = 5 mW = \(5 \times 10^{-3}\) W
- **Number of photons emitted per second (N)** = \(8 \times 10^{15}\) photons/s
- **Stopping potential (V₀)** = 2.0 V

### Step 2: Calculate the Energy of Each Photon
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