Find the maximum calculate force can act on the electron due to the nucleus in a hydrogen atom

Answer

A, B

Explanation

Since `F=(q_1q_2)/(4piin_0r^2)`
[Smallest distance between the electron and nucleus in the radius of first Bohr's Orbit]
`=((1.6 xx 10^-19) xx (1.6 xx 10^-19 xx 9 xx 10^9))/(0.53 xx 10^-10)^2`
`=(1.6 xx 1.6 xx 9 xx 10^9)/(0.53)^2 = 82.02 xx 10^-9`
`=8.2 xx 10^-8 N`.