calculate the magnetic dipolemoment corresponding to the motion of the electron in the ground state of a hydrogen atom

Answer

A, B, D

Explanation

Dipole moment `(mu) = niA=qfA`
`=e xx (me^4)/(4in_0^2h^2n^3) xx (pir_0^2n^2)`
`=(me^5 xx (pir^2n^2))/(4in0^2h^2n^3)`
`=((9.1 xx 10^-31)(1.6 xx 10^-19)^5 xx pi xx (0.53) xx 10^-20 xx1)/(4 xx (8.85 xx 1^-12)^2 xx (6.64 xx 10^-34)(1)^3)`
`=(me^5 xx (pir^2n^2))/(4in_0^2h^2n^3)`
`=0.000917 xx 10^-20`
`=9.176 xx 10^-23 A-m^2`