A hydrogen atom in ground state obsebe a photon of ultraviolet radition of wavelength `50 nm` Assuming that the entire photon energy is taken up by the electron with what kinetic energy will the up by the electron with what kinetic energy will the electron be ejected?

Answer

A, B, D

Explanation

Here `lambda = 50 nm`
Work function = Energy required to remove the electron from `n_1=1` to `n_2=oo`
`E=13.6(1/1-1/oo)=13.6`
`(hc)/lambda-13.6 = KE`
`1242/50-13.6 =KE`
implies `KE = 24.84 -13.6`
`=11.24 eV`