What potential difference should be applied across an X-ray tube to get X-ray of wavelength not less than 0.10 nm? What is the maximum energy of a photon of this X-ray in joule?

Explanation

`lambda=0.10nm=10^-12m, `
` h=6.63xx10^-34Js `
` c=3xx10^8m//s, `
` e=1.6xx10^-19C `
` lambdamin=(hc)/(eV) `
` or V=(Hc)/(elambda) `
` =(6.68xx10^-34xx3xx10)/(1.6xx10^-19xx10^-12) `
` 12.43xx10^-3V=12.4KV `
` Maximum Energy =(hc)/lamda `
` =(6.68xx10^-34 xx3xx10^8)/10^-10 `
` =19.89xx10^-16 `
` =1.989xx10^-15 `
` ~~2xx10^-15J`