If the operating potential in an X-ray tube is increased by 1%, by what percentage does the cutoff wavelength decrease?

Explanation

We know `lambda =(hc)/V `
Now, `lambda=(hc)/(1.01V)=lambda/1.01 `
` lambda'-lambda=0.01/1.01 lambda `
` %` change of wave length
` =(0.01lambda)/(1.01xxlamda)xx100=1/01`
` =0.9900 `
` 1% approximately`