The distance between the cathode (filame...

The distance between the cathode (filament) and the target in an X-ray tube is 1.5 m. If the cutoff wavelength is 30 pm, find the electric field between the cathode and the target.

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Given `d=1.5m`
` lambda=30p m =30xx10^-3nm `
` E=(hc)/lambda=1242/(30xx10^-3) `
` =4.14xx10^3eV `
` Electric field =V/d=(41.4xx10^3) /1.5 `
` 27.6xx10^3V//m `
` 27.6KV//m`

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