Calculate the binding energy of an alpha particle from the following data:
`mass of _1^1H atom = 1.007825 u`
mass of neutron `= 1.008665 u`
mass of `_4^2He atom = 4.00260 u`.
Take `1 u = 931 MeV c^(-2)`

Explanation

The alpha particle contains 2 protons and 2 neutrons. The binding energy is `B=(2 xx 1.007825 u + 2 xx 1.008665 u - 4.00260 u) c^2`
`=(0.03038 u)c^2`
= 0.03038 xx 931 MeV = 28.3 MeV`.