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The binding anergy per nucleon is 8.5 Me...

The binding anergy per nucleon is `8.5 MeV` for `A=120` and is `7.6 MeV` for `A=240` (see in figure). Suppose a nucleus with `A=240` breaks into two nuclei of nearly equal mass numbers. Calculate the energy released in the process.

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To solve the problem, we need to calculate the energy released when a nucleus with mass number \( A = 240 \) breaks into two nuclei of nearly equal mass numbers. The binding energy per nucleon for \( A = 240 \) is given as \( 7.6 \, \text{MeV} \), and for \( A = 120 \), it is \( 8.5 \, \text{MeV} \). ### Step-by-Step Solution: 1. **Identify the Mass Numbers of the Products:** Since the nucleus with \( A = 240 \) breaks into two nuclei of nearly equal mass numbers, we can assume: \[ A_1 = A_2 = \frac{240}{2} = 120 ...
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