Find the binding energy per nucleon of ``_79^197Au` if its atomic mass is 196.96 u.

Answer

D

Explanation

Given, `B = (Zm_p + Nm_n - M)c^2`
`Z = 79, N = 118`
` m_p = 1.007276u`
`M = 196.96u`
`m_n = 1.008665u`
`B = [(79 xx 1.007276 + 118 xx`
`1.008665)u - Mu]c^2`
`= 198.597274 xx 931 -196.96 xx 931`
`= 1524.302094`
So, Binding Energy per nucleon.
`= 1524.3/197 = 7.737`.