Consider the situation of the previous problem.suppose the production of the radioactive isotope starts at t=0. Find the number of active nuclei at time t.

Answer

A, B, D

Explanation

Let `N_(0)` = No. of Radioctive particle
present at time `t = 0 `
` N = No. of radio-active particle
present at time , t
Then `N = n_(0) e^(-lambda t) `
`:. The number of particlees decay
` = N _(0) - N = N_(0) - N_(0) e^(-lambda t) `
` = N _(0) (1- e ^(- lambda t) `
We know
A _(0) = lambda N_(0) , R = lambda N _(0) `
` N_(0) = (R)/( lambda) `
From the above equation
` N = N_(0) (1 - e ^(-lambda t) `
` = (R)/( lambda) (1 - e ^(- lambda t) `
( Sobstitutling the value of `N_(0)` )