A uranium rector develops thermal energy at a rate of 300 MW. Calculate the amount of ``^235U`being consumed every second .Average energy released per fission is 200 MeV.

Answer

C

Explanation

`4.4 xx 10^(-20) xx 3600 Kw = 1MeV`
`4.4 xx 10^(-20) xx 3600 Kw = 1MeV//s`
`:. 300 xx 10^(3)KW = 10^(23)/(4.4 xx 12) MeV//s`
Let no of nuclei = N
`N xx 200 = (10^23)/(4.4 xx 12)`
` N = (10^(23))/(4.4 xx 12 xx 200)`
`= 10^(21)/(24 xx 4.4)`
` 0.623 xx 10^(23) Nuclei = 235 gu U^(235)`
`:. (10^(21))/(2.4 xx 4.4) Nuclei = (235)/(6 xx 10^(23)) xx (10^(21))/(24 xx 4.4)`
`= 3.7 mg. `