Find the loss in the mass of 1 mole of an ideal monatomic gas kept in a rigid container as it cools down by `10^@C`. The gas constant `R = 8.3 J K ^(-1) mol ^(-1)`.

Explanation

Energy Possessed by a monoatomic gas
` 3 /2 n RdT `
` Now `dT = 10`
` n = 1 mete , R = 8.3J / Mol -K`
`:. E = 3 /2 xx 1 xx 8.3 xx 10`
Loss in mass ` = 1.5 xx 8.6 xx 10 / c^(2) `
` = 124.5 / 9 xx 10^(16) `
` = 13.83 xx 10^(-16) `
` = 1.38 xx 10^(-15) kg ` .