In the figure, the potentiometer wire of length `l = 100 cm` and resistance `9 Omega` is joined to a cell of emf cell of emf `E_(2) = 5 V` and internal resistance `r_(2) = 2 V` is connected as shown. The galvanometer is show no deflection when the length AC is

In the figure, the potentiometer wire AB of length L and resistance 9r is joined to the cell D fo emf E and internal resistance r. The emf of the cell C is E/2 and its internal resistance is 2r. The galvanometer G will show no deflection when the length AJ is

In the figure the potentiometer wire AB of length L and resistance 9 r is joined to the cell D of e.m.f epsilon and internal resistance r. The emf of cell C is epsilon/2 and its internal resistance is 2r.The galvanometer G will show on deflection when the length AJ is

A potentiometer wire AB having length L and resistance 12 r is joined to a cell D of emf epsi//2 and internal resistance 3r is connected. The length AJ at which the galvanometer as shown in fig. Shows no deflection is :

A potentiometer wire AB having length L and resistance 12 r is joined to a cell D of emf epsi//2 and internal resistance 3r is connected. The length AJ at which the galvanometer as shown in fig. Shows no deflection is :

An accumulator of emf 2 V and negligible internal resistance is connected across a uniform wire of length 10 m and resistance 30 Omega The appropriate terminals of a cell of emf 1.5 V and internal resistance 1 Omega is connected to one end of the wire and the other terminal of the cell is connected through a sensitive galvanometer to a slider on the wire. What is the length of the wire that will be required to produce zero deflection of the galvanometer? How will the balancing length change? (a) When a coil of resistance 5Omega is placed in series with the accumulator. (b) The cell of 1.5 V is shunted with 5 Omega resistor?