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([(1+1/(10+1/(10)))(1+1/(10+1/(10)))-(1-...

`([(1+1/(10+1/(10)))(1+1/(10+1/(10)))-(1-1/(10+1/(10)))(1-1/(10+1/(10)))])/([(1+1/(10+1/(10)))+(1-1/(10+1/(10)))])` simplifies to `(20)/(101)` (b) `(90)/(101)` (c) `(100)/(101)` (d) `(101)/(100)`

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