Find the number of ways in which six persons can be seated at a round table, so that all shall not have the same neighbours n any two arrangements.

Statement 1: the number of ways in which n persons can be seated at a round table, so that all shall not have the same neighbours in any two arrangements is (n-1)!//2. Statement 2: number of ways of arranging n different beads in circles is (n-1)!//2.

The number of ways in which four persons be seated at a round table, so that all shall not have the same neighbours in any two arrangements,is

The number of ways in which four persons be seated at a round table, so that all shall not have the same neighbours in any two arrangements,is

The number of ways in which four persons be seated at a round table, so that all shall not have the same neighbours in any two arrangements,is

The number of ways in which four persons be seated at a round table, so that all shall not have the same neighbours in any two arrangements,is

The number of ways in which four persons be seated at a round table, so that all shall not have the same neighbours in any two arrangements,is

Statement 1: the number of ways in which n persons can be seated at a round table,so that all shall not have the same neighbours in any two arrangements is (n-1)!/2. Statement 2: number of ways of arranging n different beads in circles is (n-1)!/2 .

In how many ways can 6 persons can be seated at a round table so that all shall not have the same neighbours in any two arrangements?

In how many ways can 8 persons be seated at a round table so that all shall not have the same neighbours in any two arrangements?