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Figure 5.18 shows a man standing station...

Figure 5.18 shows a man standing stationary with respect to a horizontal conveyer belt that is accelerating with ` 1 ms^(-2)` . What is the net force on the man ? If the coffecient of static friction between the man's shoes and the belt is 0.2 up to what acceleration of the belt can be man continue to be stationary relative to the belt ? (Mass of the man = 65 kg)

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Figure 5.18 shows a man standing stationary with respect to a horizontal conveyor belt that is accelerating with 1 m s^-2 . What is the net force on the man? If the coefficient of static friction between the man’s shoes and the belt is 0.2, up to what acceleration of the belt can the man continue to be stationary relative to the belt ? (Mass of the man = 65 kg.)

Figure 5.18 shows a man standing stationary with respect to a horizontal conveyor belt that is accelerating with 1 m s^2 . What is the net force on the man? If the coefficient of static friction between the man’s shoes and the belt is 0.2, up to what acceleration of the belt can the man continue to be stationary relative to the belt? (Mass of the man = 65 kg.)

A man standing stationary with respect to a horizontal conveyor belt that is accelerating with 1 m s- 2 . What is the net force on the m an ? If the coefficient of static friction between the man’s shoes and the belt is 0.2 up to what acceleration o f the belt can the man continue to be stationary relative to the belt ? (Mass of the man = 65 kg).

Figure shows a man standing stationary with respect to a horizontal conveyor belt that is accelerating with 1 m s^(-2) . What is the net force on the man? If the coefficient of static friction between the man’s shoes and the belt is 0.2, up to what acceleration of the belt can the man continue to be stationary relative to the belt ? (Mass of the man = 65 kg.)

Figure shows a man standing stationary with respect to a horizontal conveyor belt that is accelerating with 1 m s^(-2) . What is the net force on the man? If the coefficient of static friction between the man’s shoes and the belt is 0.2, up to what acceleration of the belt can the man continue to be stationary relative to the belt ? (Mass of the man = 65 kg.)

Figure shown a man standing stationary with respect to a horizontal converyor belt that is accelerationg with 1m//s^(-2) . What is the net force on the man?If the coefficient of ststic friction between the man's shoes and the belt is 0.2 upto what maximum acceleration of the belt can the man continue to be stationary relative to the belt? Mass of the man = 65kg (g =9.8m//s^(2))

Figure shown a man standing stationary with respect to a horizontal converyor belt that is accelerationg with 1m//s^(-2) . What is the net force on the man?If the coefficient of ststic friction between the man's shoes and the belt is 0.2 upto what maximum acceleration of the belt can the man continue to be stationary relative to the belt? Mass of the man = 65kg (g =9.8m//s^(2))

Figure shown a man standing stationary with respect to a horizontal converyor belt that is accelerationg with 1m//s^(-2) . What is the net force on the man?If the coefficient of ststic friction between the man's shoes and the belt is 0.2 upto what maximum acceleration of the belt can the man continue to be stationary relative to the belt? Mass of the man = 65kg (g =9.8m//s^(2))