`int_(pi//8)^(3pi//8)(cosx)/((cosx+sinx))dx=(pi)/(8)`

int_(pi//8)^(3pi//8)(1)/(1+cotx)dx=

int_(pi//4)^(3pi//4)(1)/(1+cosx)dx

int_(0)^(pi//2)(cosx)/((sinx+cosx))dx=(pi)/(4)

int_(0)^( pi/2)(cosx/(cosx+sinx))dx

int_(2pi)^((3pi)/2)cosx dx

int_(0)^(pi//6)(cosx)/((3+4sinx))dx

I : int_(0)^(pi//2)(sqrtcotx)/(sqrt(tanx)+sqrt(cotx))dx=(pi)/(4) II : int_(0)^(pi//2)(2sinx+3cosx)/(sinx+cosx)dx=(pi)/(4)

int_(pi/5)^(3pi/10) (sinxdx)/(sinx+cosx)

Prove that int(g(sinx))/(g(sinx)+g(cosx))dx = int_(0)^(pi/2)(g(cosx))/(g(sinx)+g(cosx))dx = (pi)/(4) .