The electric field part of an electromagnetic wave in vacuum is
`E=3.1(N)/(C)cos[(1.8("rad")/("m"))y+(5.4xx10^(8)("rad")/(s))t]hati`
The wavelength of this part of electromagnetic wave is

The electric field part of an electromagnetic wave in vacuum is E=3.1cos[(1.8 rad/m ​ )y+(5.4×10^8 rad/s ​ )t] i^ . The frequency corresponding to the given part of electromagnetic wave is

Suppose that the electric field part of an electromagnetic wave in vacuum is E={(3.1 N/C) cos [(1.8 rad/m)y+{5.4 xx10^(6) rad/s} t]} i. What is the wavelength lambda ?

The electric field part of an electromagnetic wave is vecE = {(3.1N//C)cos[(1.8rad//m)y+(5.4xx10^6rad//s)t]}hati) What is the frequency nu ?

Suppose that the electric field part of an electromagnetic wave in vacuum is E={(3.1 N/C) cos [(1.8 rad/m)y+{5.4 xx10^(6) rad/s} t]} i. What is the amplitude of the magnetic field part of the wave ?

Suppose that the electric field part of an electromagnetic wave in vacuum is E = {(3.1 N//C) cos [(1.8 rad//m) y + (5.4 xx 10^6 rad//s)t]} hati . What is the wavelength ?

Suppose that the electric field part of an electromagnetic wave in vacuume is E=3.1N//C cos [(1.8rad//m)y+(5.4xx10^8rad//s)t]hati (a) Wavelength is the direction of motion? (b) What is the wavelength lambda ? (c) What is the frequency v? (d) What is the amplitude of the magnetic field part of the wave? (e) Write an expression for the magnetic field part of the wave.

Suppose that the electric field part of an electromagnetic wave in vacuum is vec(E )={(3.1 N//C)cos [(1.8 rad//m)y+(5.4xx10^(6)rad//s)]}hat(i) What is the amplitude of the magnetic field part of the wave ?