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Find lim(x->0)(a x+xcosx)/(bsinx)...

Find `lim_(x->0)(a x+xcosx)/(bsinx)`

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Given that, `(lim)_(x->0)(a x+xcosx)/(bsinx)`
`=lim_(x->0) (a+cosx)/((bsinx)/x)`
`= [lim_(x->0) (a+cosx)] / [lim _(x->0) ((bsinx)/x)]`
`= (a+1)/b` [ putting `x=0`]
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