A hydrocarbons `C_(4)H_(8)`, neither decolourised bromine in carbon tetrachloride nor reacted wiith HBr. When heated to 473 K with hydrogen in presence of a nickel catalyst, a new hydrocarbon, `C_(4)H_(10)`, was formed. What was the original hydrocarbon?

A hydrocarbon, C_(4)H_(8) , neither decolourised bromine in carbontetrachloride nor reacted with hydrogen bromide. When heated to 200^(@)C with hydrogen in presence of nickel catalyst, a new hydrocarbon, C_(4)H_(10) was formed. What was the orginal hydrocarbon?

A hydrocarbon of formula C_(6)H_(12) decolourises bromine water. It also gives precipatate with ammonical AgNO_(3) solution. The hydrocarbon is

A hydrocarbon, ‘X’(C_(3)H_(4)) decolourise bromine in carbon tetrachloride forming ‘Y’ . ‘X’ gave a red precipitate of a compound ‘Z’ with ammonical cuprous chloride and formed a carbonyl compound with dilute sulphuric acid in the presence of Hg^(+2) ions. X, Y, and Z are given by the set -

The formula of hydrocarbon is C_(4)H_(6) ? To which family does it belong ?

The formula of hydrocarbon is C_(4)H_(6) ? To which family does it belong ?

On heating a mixture of hydrogen and carbon monoxide gases at 300°C in the presence of nickel (catalyst) ………is formed.

A hydrocarbon with molecular formula, C_(4)H_(6) undergoes the following reactions : A. Decolourised molecular bromine. B. Reacted with HBr. C. Addition of ozone and then cleavage of the ozonide by Zn//H_(2)O gave the product C_(4)H_(6)O_(2) . Then, the structure of the hydrocarbon is

C_(4)H_(10) (hydrocarbon) is the main constituent of