If f(x)=2x + tanx and g(x) is the inverse of f(x), then value of `g'(pi/2+1)`is

If f(x)=x+tanx and g(x) is the inverse of f(x), then differentiation of g(x) is (a) 1/(1+[g(x)-x]^2) (b) 1/(2-[g(x)+x]^2) (c) 1/(2+[g(x)-x]^2) (d) none of these

If f(x)=x+tanx and g(x) is the inverse of f(x) , then differentiation of g(x) is (a) 1/(1+[g(x)-x]^2) (b) 1/(2-[g(x)+x]^2) (c)1/(2+[g(x)-x]^2) (d) none of these

If f(x)=x+tanx and g(x) is the inverse of f(x) , then differentiation of g(x) is (a) 1/(1+[g(x)-x]^2) (b) 1/(2-[g(x)+x]^2) (c)1/(2+[g(x)-x]^2) (d) none of these

If f(x)=x+tanx and g(x) is inverse of f(x) then g^(')(x) is equal to

Let f(x)=x^(3)+3x+2 and g(x) is inverse function of f(x) then the value of g'(6) is

Consider the function f(x)=tan^(-1){(3x-2)/(3+2x)}, AA x ge 0. If g(x) is the inverse function of f(x) , then the value of g'((pi)/(4)) is equal to

Consider the function f(x)=tan^(-1){(3x-2)/(3+2x)}, AA x ge 0. If g(x) is the inverse function of f(x) , then the value of g'((pi)/(4)) is equal to

Let f(x)=(1)/(1+x^(2)) and g(x) is the inverse of f(x) ,then find g(x)

If f(x)=x+tan x and g(x) is inverse of f(x) then g'(x) is equal to (1)(1)/(1+(g(x)-x)^(2))(2)(1)/(1-(g(x)-x)^(2))(1)/(2+(g(x)-x)^(2))(4)(1)/(2-(g(x)-x)^(2))

If f (x) = x^(2) +x ^(4) +log x and g is the inverse of f, then g'(2) is: