Home
Class 12
PHYSICS
After absorbing a slowly moving neutrons...

After absorbing a slowly moving neutrons of mass `m_(N)` (momentum ~0) a nucleus of mass M breaks into two nuclie of mass `m_(1) and 5m_(1)(6m_(1)=M+m_(N))`, respectively . If the de-Broglie wavelength of the nucleus with mass `m_(1) is lambda`, then de Broglie wavelength of the other nucleus will be

Promotional Banner

Similar Questions

Explore conceptually related problems

After absorbing a slowly moving neutrons of mass m_(N) (momentum ~0) a nucleus of mass M breaks into two nucleii of mass m_(1) and 5m_(1)(6m_(1)=M+m_(N)) , respectively . If the de-Broglie wavelength of the nucleus with mass m_(1) is lambda , then de Broglie wavelength of the other nucleus will be

After absorbing a slowly moving neutrons of mass m_(N) (momentum ~0) a nucleus of mass M breaks into two nucleii of mass m_(1) and 5m_(1)(6m_(1)=M+m_(N)) , respectively . If the de-Broglie wavelength of the nucleus with mass m_(1) is lambda , then de Broglie wavelength of the other nucleus will be

A nucleus of mass M is initially at rest.It absorb neutron having m_(N) rest mass compound nucleus divided in two nucleus of m_(1) and 5 m_(1) .If wavelength of nucleus with mass m_(1) is lambda ,then wavelength of other nucleus will be…..

A particle of mass M at rest decays into two particles of masses m_(1) and m_(2) having non-zero velocities. The ratio of the de Broglie wavelengths of the particles 1 and 2 is

A particle of mass M at rest decay's into two particle of masses m_(1) and m_(2) having non zero velocity. The ratio of the de Broglie wavelengths of the masses lambda _(1) // lambda_(2) is

A particle of mass M at rest decays into two particles of masses m_1 and m_2 having velocities V_1 and V_2 respectively. Find the ratio of de- Broglie wavelengths of the two particles

A particle of mass M at rest decays into two masses m_(1) and m_2 with non zero velocities. The ratio of de-Broglie wavelengths of the particles (lamda_(1))/(lamda_(2)) is