Home
Class 12
MATHS
The area of the region bounded by y=sinx...

The area of the region bounded by `y=sinx`, `y=cosx` in the first quadrant is

Text Solution

Verified by Experts

Area=`int_0^(pi/4) sinxdx+int_(pi/4)^(pi/2) cosxdx`
`=(cosx)_0^(pi/4)+(sinx)_(pi/4)^(pi/2)`
`=1-cospi/4+sinpi/2-sinpi/4`
`1-1/sqrt2+1-1/sqrt2=2-sqrt2`
option d is correct.
Promotional Banner

Similar Questions

Explore conceptually related problems

Find the area of the region bounded by y=sqrtx ,\ x=2y+3 in the first quadrant and x-axis.

The area of the region bounded by x^2=16y , y=1 and x=0 in the first quadrant is…………

Find the area of the region bounded by y=4x^2 ,x=0,y=1,y=4 in the first quadrant.

Find the area of region bounded by y^(2)=x,x=4,x=6 and x-axis in the first quadrant.

Find the area of the region bounded by x^(3)=y-3,y=4,y=6 and y-axis in the first quadrant.

Find the area of the region bounded by y = sinx, y = cosx and ordinates x = 0, x = pi//2 .